76 lines
2.6 KiB
MySQL
76 lines
2.6 KiB
MySQL
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-- 检查样品状态与工单的一致性
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-- 用于诊断"删除工单后仍提示已有工单"的问题
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-- 1. 查看样品状态分布
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SELECT
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'样品状态分布' AS 检查项,
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status AS 状态值,
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CASE
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WHEN status = '0' THEN '待测试'
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WHEN status = '1' THEN '测试中'
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WHEN status = '2' THEN '已完成'
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ELSE '未知'
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END AS 状态名称,
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COUNT(*) AS 数量
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FROM warehouse_sample
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GROUP BY status
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ORDER BY status;
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-- 2. 查看工单数量
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SELECT
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'工单数量' AS 检查项,
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COUNT(*) AS 总数,
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COUNT(CASE WHEN order_id IS NULL THEN 1 END) AS 未汇总数量,
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COUNT(CASE WHEN order_id IS NOT NULL THEN 1 END) AS 已汇总数量
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FROM test_work_order;
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-- 3. 查找状态为"测试中"但没有工单的样品（数据不一致）
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SELECT
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'不一致的样品' AS 检查项,
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s.sample_id AS 样品ID,
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s.sample_sn AS 样品SN,
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s.status AS 状态,
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CASE
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WHEN s.status = '0' THEN '待测试'
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WHEN s.status = '1' THEN '测试中'
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WHEN s.status = '2' THEN '已完成'
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ELSE '未知'
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END AS 状态名称,
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COUNT(wo.id) AS 工单数量
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FROM warehouse_sample s
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LEFT JOIN test_eut te ON s.sample_sn = te.sn
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LEFT JOIN test_work_order wo ON te.id = wo.test_eut_id AND wo.order_id IS NULL
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WHERE s.status != '0' -- 非待测试状态
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GROUP BY s.sample_id, s.sample_sn, s.status
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HAVING COUNT(wo.id) = 0;
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-- 4. 查看最近的样品和工单关联情况
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SELECT
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'最近样品工单关联' AS 检查项,
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s.sample_id AS 样品ID,
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s.sample_sn AS 样品SN,
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s.status AS 样品状态,
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te.id AS TestEutID,
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COUNT(wo.id) AS 工单数量,
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GROUP_CONCAT(wo.id) AS 工单ID列表
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FROM warehouse_sample s
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LEFT JOIN test_eut te ON s.sample_sn = te.sn
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LEFT JOIN test_work_order wo ON te.id = wo.test_eut_id AND wo.order_id IS NULL
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GROUP BY s.sample_id, s.sample_sn, s.status, te.id
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ORDER BY s.sample_id DESC
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LIMIT 10;
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-- 5. 统计结果
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SELECT
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'统计结果' AS 检查项,
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(SELECT COUNT(*) FROM warehouse_sample) AS 样品总数,
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(SELECT COUNT(*) FROM warehouse_sample WHERE status = '0') AS 待测试样品数,
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(SELECT COUNT(*) FROM warehouse_sample WHERE status = '1') AS 测试中样品数,
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(SELECT COUNT(*) FROM warehouse_sample WHERE status = '2') AS 已完成样品数,
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(SELECT COUNT(*) FROM test_work_order WHERE order_id IS NULL) AS 未汇总工单数,
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(SELECT COUNT(DISTINCT s.sample_id)
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FROM warehouse_sample s
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LEFT JOIN test_eut te ON s.sample_sn = te.sn
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LEFT JOIN test_work_order wo ON te.id = wo.test_eut_id AND wo.order_id IS NULL
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WHERE s.status != '0' AND wo.id IS NULL) AS 不一致样品数;
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